[Techinfo] PHP segítség

2021. Jan. 20., Sze, 07:53:49 CET

Szép napot Mindenkinek!

Kérnék szépen pár szakértő szemet, mert nem találom mi a hiba állandóan ezt
írja ki:
*Parse error*: syntax error, unexpected '}', expecting end of file in
*C:\xampp\htdocs\loginx\edit.php* on line *71*
pedig kell a: "}"

A kódom:

<?php
include "connection.php";
$id=$_GET["id"];

$firstname="";
$lastname="";
$email="";
$contact="";

$res=mysqli_query($link,"select * from table1 where id=$id");
while($row=mysqli_fetch_array($res))
{
$firstname=$row["firstname"];
$lastname=$row["lastname"];
$email=$row["email"];
$contact=$row["contact"];
}
?>

<!DOCTYPE html>
<html lang="en">
<head>
  <title>Bootstrap Example</title>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width, initial-scale=1">
  <link rel="stylesheet" href="
https://maxcdn.bootstrapcdn.com/bootstrap/3.4.1/css/bootstrap.min.css">
  <script src="
https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
  <script src="
https://maxcdn.bootstrapcdn.com/bootstrap/3.4.1/js/bootstrap.min.js
"></script>
</head>
<body>

<div class="container">
<div class="col-lg-4">
  <h2>Basic Database Connection</h2>
  <form action="" name="form1" method="post">
    <div class="form-group">
      <label for="email">firstname</label>
      <input type="text" class="form-control" id="firstname"
placeholder="Enter firstname" name="firstname" value="<?php echo
$firstname; ?>">
    </div>
    <div class="form-group">
      <label for="pwd">lastname</label>
      <input type="text" class="form-control" id="lastname"
placeholder="Enter lastname" name="lastname" value="<?php echo $lastname;
?>">
    </div>
<div class="form-group">
      <label for="pwd">email</label>
      <input type="text" class="form-control" id="email" placeholder="Enter
email" name="email" value="<?php echo $email; ?>">
    </div>
    <div class="form-group">
      <label for="pwd">contact</label>
      <input type="text" class="form-control" id="contact"
placeholder="Enter contact" name="contact" value="<?php echo $contact; ?>">
    </div>

<button type="submit" name="update" class="btn btn-default">Update</button>

  </form>
</div>
</div>

</body>

<?php>
if(isset($_POST["update"]))
{
mysqli_query($link,"update table1 set
firstname='$_POST[firstname]',lastname='$_POST[lastname]',email='$_POST[email]',contact='$_POST[contact]'
where id=$id");
?>
<script type="text/javascript">
windows.location.href="index.php";
</script>
<?php
}
?>

</html>

Előre is köszönöm a szemeteket!

Szép napot!
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